Problem
You have a 2-D grid
of size m x n
representing a box, and you have n
balls. The box is open on the top and bottom sides.
Each cell in the box has a diagonal board spanning two corners of the cell that can redirect a ball to the right or to the left.
- A board that redirects the ball to the right spans the top-left corner to the bottom-right corner and is represented in the grid as
1
. - A board that redirects the ball to the left spans the top-right corner to the bottom-left corner and is represented in the grid as
-1
.
We drop one ball at the top of each column of the box. Each ball can get stuck in the box or fall out of the bottom. A ball gets stuck if it hits a “V” shaped pattern between two boards or if a board redirects the ball into either wall of the box.
Return an array answer
of size n
where answer[i]
is the column that the ball falls out of at the bottom after dropping the ball from the iᵗʰ
column at the top, or -1
if the ball gets stuck in the box.
https://leetcode.cn/problems/where-will-the-ball-fall/
Example 1:
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Input:
grid = [[1,1,1,-1,-1],[1,1,1,-1,-1],[-1,-1,-1,1,1],[1,1,1,1,-1],[-1,-1,-1,-1,-1]]
Output:[1,-1,-1,-1,-1]
Explanation: This example is shown in the photo.
Ball b0 is dropped at column 0 and falls out of the box at column 1.
Ball b1 is dropped at column 1 and will get stuck in the box between column 2 and 3 and row 1.
Ball b2 is dropped at column 2 and will get stuck on the box between column 2 and 3 and row 0.
Ball b3 is dropped at column 3 and will get stuck on the box between column 2 and 3 and row 0.
Ball b4 is dropped at column 4 and will get stuck on the box between column 2 and 3 and row 1.
Example 2:
Input:
grid = [[-1]]
Output:[-1]
Explanation: The ball gets stuck against the left wall.
Example 3:
Input:
grid = [[1,1,1,1,1,1],[-1,-1,-1,-1,-1,-1],[1,1,1,1,1,1],[-1,-1,-1,-1,-1,-1]]
Output:[0,1,2,3,4,-1]
Constraints:
m == grid.length
n == grid[i].length
1 <= m, n <= 100
grid[i][j]
is1
or-1
.
Test Cases
1 | class Solution: |
1 | import pytest |
Thoughts
直接用模拟法,模拟每个球的移动路径,计算出最终落到哪里。
如果一个球落入 grid 中某一行 row 的第 src 列,那么球会往 dest = src + row[src]
列滚动。但如果 dest 超出 [0, n)
区间,就会被左右边界挡住并停在那里。类似地,如果 grid[dest] ≠ grid[src]
,说明形成了一个 “V”,也就停住了。其他情况,球会落入下一行的 dest 列,重复同样的判断直到球在某行被卡住或者从最后一行漏下去为止。
每个球最多需要 O(m)
时间。总共时间复杂度 O(m * n)
,附加的空间复杂度 O(1)
。
Code
1 | class Solution: |