Problem

Given a 2D grid of size m x n and an integer k. You need to shift the grid k times.

In one shift operation:

  • Element at grid[i][j] moves to grid[i][j + 1].
  • Element at grid[i][n - 1] moves to grid[i + 1][0].
  • Element at grid[m - 1][n - 1] moves to grid[0][0].

Return the 2D grid after applying shift operation k times.

https://leetcode.com/problems/shift-2d-grid/

Example 1:

Input: grid = [[1,2,3],[4,5,6],[7,8,9]], k = 1
Output: [[9,1,2],[3,4,5],[6,7,8]]

Example 2:

Input: grid = [[3,8,1,9],[19,7,2,5],[4,6,11,10],[12,0,21,13]], k = 4
Output: [[12,0,21,13],[3,8,1,9],[19,7,2,5],[4,6,11,10]]

Example 3:

Input: grid = [[1,2,3],[4,5,6],[7,8,9]], k = 9
Output: [[1,2,3],[4,5,6],[7,8,9]]

Constraints:

  • m == grid.length
  • n == grid[i].length
  • 1 <= m <= 50
  • 1 <= n <= 50
  • -1000 <= grid[i][j] <= 1000
  • 0 <= k <= 100

Test Cases

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class Solution:
def shiftGrid(self, grid: List[List[int]], k: int) -> List[List[int]]:
solution_test.py
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import copy
import pytest

from solution import Solution


@pytest.mark.parametrize('grid, k, expected', [
([[1,2,3],[4,5,6],[7,8,9]], 1, [[9,1,2],[3,4,5],[6,7,8]]),
([[3,8,1,9],[19,7,2,5],[4,6,11,10],[12,0,21,13]], 4, [[12,0,21,13],[3,8,1,9],[19,7,2,5],[4,6,11,10]]),
([[1,2,3],[4,5,6],[7,8,9]], 9, [[1,2,3],[4,5,6],[7,8,9]]),
])
@pytest.mark.parametrize('sol', [Solution()])
def test_solution(sol, grid, k, expected):
assert sol.shiftGrid(copy.deepcopy(grid), k) == expected

Thoughts

In-place 轮换比较麻烦,一般的实现方式也是需要用 O(m * n) 的辅助空间。直接生成新的二维数组写入轮换后的结果即可。

Code

solution.py
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class Solution:
def shiftGrid(self, grid: list[list[int]], k: int) -> list[list[int]]:
m = len(grid)
n = len(grid[0])
mn = m * n
k %= mn
if k == 0: return grid

res = [[0] * n for _ in range(m)]
for i in range(m):
for j in range(n):
r, c = divmod(k, n)
res[r][c] = grid[i][j]
k = (k + 1) % mn

return res