Problem
Given a 2D grid
of size m x n
and an integer k
. You need to shift the grid
k
times.
In one shift operation:
- Element at
grid[i][j]
moves togrid[i][j + 1]
. - Element at
grid[i][n - 1]
moves togrid[i + 1][0]
. - Element at
grid[m - 1][n - 1]
moves togrid[0][0]
.
Return the 2D grid after applying shift operation k
times.
https://leetcode.com/problems/shift-2d-grid/
Example 1:
Input:
grid = [[1,2,3],[4,5,6],[7,8,9]], k = 1
Output:[[9,1,2],[3,4,5],[6,7,8]]
Example 2:
Input:
grid = [[3,8,1,9],[19,7,2,5],[4,6,11,10],[12,0,21,13]], k = 4
Output:[[12,0,21,13],[3,8,1,9],[19,7,2,5],[4,6,11,10]]
Example 3:
Input:
grid = [[1,2,3],[4,5,6],[7,8,9]], k = 9
Output:[[1,2,3],[4,5,6],[7,8,9]]
Constraints:
m == grid.length
n == grid[i].length
1 <= m <= 50
1 <= n <= 50
-1000 <= grid[i][j] <= 1000
0 <= k <= 100
Test Cases
1 | class Solution: |
1 | import copy |
Thoughts
In-place 轮换比较麻烦,一般的实现方式也是需要用 O(m * n)
的辅助空间。直接生成新的二维数组写入轮换后的结果即可。
Code
1 | class Solution: |