825. Friends Of Appropriate Ages
Problem
There are n persons on a social media website. You are given an integer array ages where ages[i] is the age of the iᵗʰ person.
A Person x will not send a friend request to a person y (x != y) if any of the following conditions is true:
age[y] <= 0.5 * age[x] + 7age[y] > age[x]age[y] > 100 && age[x] < 100
Otherwise, x will send a friend request to y.
Note that if x sends a request to y, y will not necessarily send a request to x. Also, a person will not send a friend request to himself.
Return the total number of friend requests made.
https://leetcode.cn/problems/friends-of-appropriate-ages/
Example 1:
Input:
ages = [16,16]
Output:2
Explanation: 2 people friend request each other.
Example 2:
Input:
ages = [16,17,18]
Output:2
Explanation: Friend requests are made 17 -> 16, 18 -> 17.
Example 3:
Input:
ages = [20,30,100,110,120]
Output:3
Explanation: Friend requests are made 110 -> 100, 120 -> 110, 120 -> 100.
Constraints:
n == ages.length1 <= n <= 2 * 10⁴1 <= ages[i] <= 120
Test Cases
class Solution:
def numFriendRequests(self, ages: List[int]) -> int:import pytest
from solution import Solution
@pytest.mark.parametrize('ages, expected', [
([16,16], 2),
([16,17,18], 2),
([20,30,100,110,120], 3),
])
class Test:
def test_solution(self, ages, expected):
sol = Solution()
assert sol.numFriendRequests(ages) == expected
Thoughts
第三个条件似乎没用?当 age[y] > 100 && age[x] < 100 成立的时候,第二条的 age[y] > age[x] 一定成立。
条件一对应图中斜线下方的梯形区域,条件二对应对角线上方的三角形区域,条件三是条件二区域内部靠上部分的那个长条矩形。
排除掉三个条件的限制,图中网格填充的三角形区域是会发送邀请的 age[y] 和 age[x] 的关系,即 0.5 * age[x] + 7 < age[y] <= age[x]。
因为年龄数值是 1 到 120 之间的整数,用桶排序,统计每个年龄的人数,并算出小于等于每个年龄的总人数。
对于任何一个年龄,计算这个年龄的人会给哪个年龄范围的人发邀请,算出这个年龄区间的总人数。
空间复杂度 O(1),时间复杂度 O(n)。
Code
from typing import List
class Solution:
def numFriendRequests(self, ages: List[int]) -> int:
counts = [0] * 121
for age in ages:
counts[age] += 1
for age in range(1, len(counts)):
counts[age] += counts[age - 1]
total = 0
for age_x in range(1, len(counts)):
count_x = counts[age_x] - counts[age_x - 1]
if count_x == 0:
continue
exclude_age_y = (age_x >> 1) + 7
if age_x < exclude_age_y + 1:
continue
count_y = counts[age_x] - counts[exclude_age_y] - 1 # Exclude himself.
total += count_x * count_y
return total
评论需要 JavaScript。