2545. Sort the Students by Their Kth Score
Problem
There is a class with m students and n exams. You are given a 0-indexed m x n integer matrix score, where each row represents one student and score[i][j] denotes the score the iᵗʰ student got in the jᵗʰ exam. The matrix score contains distinct integers only.
You are also given an integer k. Sort the students (i.e., the rows of the matrix) by their scores in the kᵗʰ (0-indexed) exam from the highest to the lowest.
Return the matrix after sorting it.
https://leetcode.cn/problems/sort-the-students-by-their-kth-score/
Example 1:

Input:
score = [[10,6,9,1],[7,5,11,2],[4,8,3,15]], k = 2
Output:[[7,5,11,2],[10,6,9,1],[4,8,3,15]]
Explanation: In the above diagram, S denotes the student, while E denotes the exam.
- The student with index 1 scored 11 in exam 2, which is the highest score, so they got first place.
- The student with index 0 scored 9 in exam 2, which is the second highest score, so they got second place.
- The student with index 2 scored 3 in exam 2, which is the lowest score, so they got third place.
Example 2:

Input:
score = [[3,4],[5,6]], k = 0
Output:[[5,6],[3,4]]
Explanation: In the above diagram, S denotes the student, while E denotes the exam.
- The student with index 1 scored 5 in exam 0, which is the highest score, so they got first place.
- The student with index 0 scored 3 in exam 0, which is the lowest score, so they got second place.
Constraints:
m == score.lengthn == score[i].length1 <= m, n <= 2501 <= score[i][j] <= 10⁵scoreconsists of distinct integers.0 <= k < n
Test Cases
class Solution:
def sortTheStudents(self, score: List[List[int]], k: int) -> List[List[int]]:import pytest
from solution import Solution
@pytest.mark.parametrize('score, k, expected', [
([[10,6,9,1],[7,5,11,2],[4,8,3,15]], 2, [[7,5,11,2],[10,6,9,1],[4,8,3,15]]),
([[3,4],[5,6]], 0, [[5,6],[3,4]]),
])
@pytest.mark.parametrize('sol', [Solution()])
def test_solution(sol, score, k, expected):
assert sol.sortTheStudents(score.copy(), k) == expected
Thoughts
这题用 Python 实现是不是某种程度上的「作弊」呢……
Code
class Solution:
def sortTheStudents(self, score: list[list[int]], k: int) -> list[list[int]]:
score.sort(key=lambda row: row[k], reverse=True)
return score
评论需要 JavaScript。