Problem
You are given a 0-indexed integer array nums
of length n
.
nums
contains a valid split at index i
if the following are true:
- The sum of the first
i + 1
elements is greater than or equal to the sum of the lastn - i - 1
elements. - There is at least one element to the right of
i
. That is,0 <= i < n - 1
.
Return the number of valid splits in nums
.
https://leetcode.com/problems/number-of-ways-to-split-array/
Example 1:
Input:
nums = [10,4,-8,7]
Output:2
Explanation:
There are three ways of splitting nums into two non-empty parts:
- Split nums at index 0. Then, the first part is
[10]
, and its sum is 10. The second part is[4,-8,7]
, and its sum is 3. Since10 >= 3
,i = 0
is a valid split.- Split nums at index 1. Then, the first part is
[10,4]
, and its sum is 14. The second part is[-8,7]
, and its sum is -1. Since14 >= -1
,i = 1
is a valid split.- Split nums at index 2. Then, the first part is
[10,4,-8]
, and its sum is 6. The second part is[7]
, and its sum is 7. Since6 < 7
,i = 2
is not a valid split.Thus, the number of valid splits in nums is 2.
Example 2:
Input:
nums = [2,3,1,0]
Output:2
Explanation:
There are two valid splits in nums:
- Split nums at index 1. Then, the first part is
[2,3]
, and its sum is 5. The second part is[1,0]
, and its sum is 1. Since5 >= 1
,i = 1
is a valid split.- Split nums at index 2. Then, the first part is
[2,3,1]
, and its sum is 6. The second part is[0]
, and its sum is 0. Since6 >= 0
,i = 2
is a valid split.
Constraints:
2 <= nums.length <= 10⁵
-10⁵ <= nums[i] <= 10⁵
Test Cases
1 | Tclass Solution: |
1 | import pytest |
Thoughts
先计算出整个 nums 的总和。
从 i = 0
开始遍历,累加左半数组的和,根据总和可以算出右半数组之和,比较即可。
Code
1 | class Solution: |