Problem
You are given a 0-indexed integer array nums of length n.
nums contains a valid split at index i if the following are true:
- The sum of the first
i + 1elements is greater than or equal to the sum of the lastn - i - 1elements. - There is at least one element to the right of
i. That is,0 <= i < n - 1.
Return the number of valid splits in nums.
https://leetcode.com/problems/number-of-ways-to-split-array/
Example 1:
Input:
nums = [10,4,-8,7]
Output:2
Explanation:
There are three ways of splitting nums into two non-empty parts:
- Split nums at index 0. Then, the first part is
[10], and its sum is 10. The second part is[4,-8,7], and its sum is 3. Since10 >= 3,i = 0is a valid split.- Split nums at index 1. Then, the first part is
[10,4], and its sum is 14. The second part is[-8,7], and its sum is -1. Since14 >= -1,i = 1is a valid split.- Split nums at index 2. Then, the first part is
[10,4,-8], and its sum is 6. The second part is[7], and its sum is 7. Since6 < 7,i = 2is not a valid split.Thus, the number of valid splits in nums is 2.
Example 2:
Input:
nums = [2,3,1,0]
Output:2
Explanation:
There are two valid splits in nums:
- Split nums at index 1. Then, the first part is
[2,3], and its sum is 5. The second part is[1,0], and its sum is 1. Since5 >= 1,i = 1is a valid split.- Split nums at index 2. Then, the first part is
[2,3,1], and its sum is 6. The second part is[0], and its sum is 0. Since6 >= 0,i = 2is a valid split.
Constraints:
2 <= nums.length <= 10⁵-10⁵ <= nums[i] <= 10⁵
Test Cases
1 | Tclass Solution: |
1 | import pytest |
Thoughts
先计算出整个 nums 的总和。
从 i = 0 开始遍历,累加左半数组的和,根据总和可以算出右半数组之和,比较即可。
Code
1 | class Solution: |